(2x+2)(5x-5)=0

Solution for (2x+2)(5x-5)=0 equation:

Simplifying
(2x + 2)(5x + -5) = 0

Reorder the terms:
(2 + 2x)(5x + -5) = 0

Reorder the terms:
(2 + 2x)(-5 + 5x) = 0

Multiply (2 + 2x) * (-5 + 5x)
(2(-5 + 5x) + 2x * (-5 + 5x)) = 0
((-5 * 2 + 5x * 2) + 2x * (-5 + 5x)) = 0
((-10 + 10x) + 2x * (-5 + 5x)) = 0
(-10 + 10x + (-5 * 2x + 5x * 2x)) = 0
(-10 + 10x + (-10x + 10x2)) = 0

Combine like terms: 10x + -10x = 0
(-10 + 0 + 10x2) = 0
(-10 + 10x2) = 0

Solving
-10 + 10x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 10x2 = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 10x2 = 0 + 10
10x2 = 0 + 10

Combine like terms: 0 + 10 = 10
10x2 = 10

Divide each side by '10'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}