(2x+2)(3x+7)=0

Solution for (2x+2)(3x+7)=0 equation:

(2x+2)(3x+7)=0

We multiply parentheses ..

(+6x^2+14x+6x+14)=0

We get rid of parentheses

6x^2+14x+6x+14=0

We add all the numbers together, and all the variables

6x^2+20x+14=0

a = 6; b = 20; c = +14;
Δ = b2-4ac
Δ = 202-4·6·14
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8}{2*6}=\frac{-28}{12}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8}{2*6}=\frac{-12}{12}
=-1
$