(2x+1x)(1x-1)=(1-1)(1x-1)

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Solution for (2x+1x)(1x-1)=(1-1)(1x-1) equation:


Simplifying
(2x + 1x)(1x + -1) = (1 + -1)(1x + -1)

Combine like terms: 2x + 1x = 3x
(3x)(1x + -1) = (1 + -1)(1x + -1)

Remove parenthesis around (3x)
3x(1x + -1) = (1 + -1)(1x + -1)

Reorder the terms:
3x(-1 + 1x) = (1 + -1)(1x + -1)
(-1 * 3x + 1x * 3x) = (1 + -1)(1x + -1)
(-3x + 3x2) = (1 + -1)(1x + -1)

Combine like terms: 1 + -1 = 0
-3x + 3x2 = (0)(1x + -1)

Reorder the terms:
-3x + 3x2 = 0(-1 + 1x)

Anything times zero is zero.
-3x + 3x2 = 0(-1 + 1x)

Solving
-3x + 3x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '3x'.
3x(-1 + x) = 0

Ignore the factor 3.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(-1 + x)' equal to zero and attempt to solve: Simplifying -1 + x = 0 Solving -1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + x = 0 + 1 x = 0 + 1 Combine like terms: 0 + 1 = 1 x = 1 Simplifying x = 1

Solution

x = {0, 1}

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