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(2x+17)/(x+7)=x+5
We move all terms to the left:
(2x+17)/(x+7)-(x+5)=0
Domain of the equation: (x+7)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
x!=-7
x∈R
(2x+17)/(x+7)-x-5=0
We multiply all the terms by the denominator
(2x+17)-x*(x+7)-5*(x+7)=0
We multiply parentheses
-x^2+(2x+17)-7x-5x-35=0
We get rid of parentheses
-x^2+2x-7x-5x+17-35=0
We add all the numbers together, and all the variables
-1x^2-10x-18=0
a = -1; b = -10; c = -18;
Δ = b2-4ac
Δ = -102-4·(-1)·(-18)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{7}}{2*-1}=\frac{10-2\sqrt{7}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{7}}{2*-1}=\frac{10+2\sqrt{7}}{-2} $
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