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(2x+16)(44+4x)=180
We move all terms to the left:
(2x+16)(44+4x)-(180)=0
We add all the numbers together, and all the variables
(2x+16)(4x+44)-180=0
We multiply parentheses ..
(+8x^2+88x+64x+704)-180=0
We get rid of parentheses
8x^2+88x+64x+704-180=0
We add all the numbers together, and all the variables
8x^2+152x+524=0
a = 8; b = 152; c = +524;
Δ = b2-4ac
Δ = 1522-4·8·524
Δ = 6336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6336}=\sqrt{576*11}=\sqrt{576}*\sqrt{11}=24\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(152)-24\sqrt{11}}{2*8}=\frac{-152-24\sqrt{11}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(152)+24\sqrt{11}}{2*8}=\frac{-152+24\sqrt{11}}{16} $
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