(2x+16)(3x+5)=0

Solution for (2x+16)(3x+5)=0 equation:

(2x+16)(3x+5)=0

We multiply parentheses ..

(+6x^2+10x+48x+80)=0

We get rid of parentheses

6x^2+10x+48x+80=0

We add all the numbers together, and all the variables

6x^2+58x+80=0

a = 6; b = 58; c = +80;
Δ = b2-4ac
Δ = 582-4·6·80
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-38}{2*6}=\frac{-96}{12}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+38}{2*6}=\frac{-20}{12}
=-1+2/3
$