(2x+15)+(3x+20)+(2x+15)+(3x+20)=50

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Solution for (2x+15)+(3x+20)+(2x+15)+(3x+20)=50 equation: 



(2x+15)+(3x+20)+(2x+15)+(3x+20)=50

We move all terms to the left:

(2x+15)+(3x+20)+(2x+15)+(3x+20)-(50)=0

We get rid of parentheses

2x+3x+2x+3x+15+20+15+20-50=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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