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(2x+13)(2x+21)=195
We move all terms to the left:
(2x+13)(2x+21)-(195)=0
We multiply parentheses ..
(+4x^2+42x+26x+273)-195=0
We get rid of parentheses
4x^2+42x+26x+273-195=0
We add all the numbers together, and all the variables
4x^2+68x+78=0
a = 4; b = 68; c = +78;
Δ = b2-4ac
Δ = 682-4·4·78
Δ = 3376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3376}=\sqrt{16*211}=\sqrt{16}*\sqrt{211}=4\sqrt{211}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-4\sqrt{211}}{2*4}=\frac{-68-4\sqrt{211}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+4\sqrt{211}}{2*4}=\frac{-68+4\sqrt{211}}{8} $
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