(2x+12)=(7x-10)+(3x+16)

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Solution for (2x+12)=(7x-10)+(3x+16) equation: 



(2x+12)=(7x-10)+(3x+16)

We move all terms to the left:

(2x+12)-((7x-10)+(3x+16))=0

We get rid of parentheses

2x-((7x-10)+(3x+16))+12=0



We calculate terms in parentheses: -((7x-10)+(3x+16)), so:

(7x-10)+(3x+16)

We get rid of parentheses

7x+3x-10+16

We add all the numbers together, and all the variables

10x+6

Back to the equation:

-(10x+6)



We get rid of parentheses

2x-10x-6+12=0

We add all the numbers together, and all the variables

-8x+6=0

We move all terms containing x to the left, all other terms to the right

-8x=-6

x=-6/-8

x=3/4

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