(2x+12)=(3x-17)+75

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Solution for (2x+12)=(3x-17)+75 equation: 



(2x+12)=(3x-17)+75

We move all terms to the left:

(2x+12)-((3x-17)+75)=0

We get rid of parentheses

2x-((3x-17)+75)+12=0



We calculate terms in parentheses: -((3x-17)+75), so:

(3x-17)+75

We get rid of parentheses

3x-17+75

We add all the numbers together, and all the variables

3x+58

Back to the equation:

-(3x+58)



We get rid of parentheses

2x-3x-58+12=0

We add all the numbers together, and all the variables

-1x-46=0

We move all terms containing x to the left, all other terms to the right

-x=46

x=46/-1

x=-46

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