(2x+12)+(8x+8)=(2x+4)

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Solution for (2x+12)+(8x+8)=(2x+4) equation:



(2x+12)+(8x+8)=(2x+4)
We move all terms to the left:
(2x+12)+(8x+8)-((2x+4))=0
We get rid of parentheses
2x+8x-((2x+4))+12+8=0
We calculate terms in parentheses: -((2x+4)), so:
(2x+4)
We get rid of parentheses
2x+4
Back to the equation:
-(2x+4)
We add all the numbers together, and all the variables
10x-(2x+4)+20=0
We get rid of parentheses
10x-2x-4+20=0
We add all the numbers together, and all the variables
8x+16=0
We move all terms containing x to the left, all other terms to the right
8x=-16
x=-16/8
x=-2

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