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(2x+11)(5x+3)=0
We multiply parentheses ..
(+10x^2+6x+55x+33)=0
We get rid of parentheses
10x^2+6x+55x+33=0
We add all the numbers together, and all the variables
10x^2+61x+33=0
a = 10; b = 61; c = +33;
Δ = b2-4ac
Δ = 612-4·10·33
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-49}{2*10}=\frac{-110}{20} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+49}{2*10}=\frac{-12}{20} =-3/5 $
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