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x in (-oo:+oo)
(2*x+10)/2 = (3*x+15)/3 // - (3*x+15)/3
(2*x+10)/2-((3*x+15)/3) = 0
(2*x+10)/2+(-1*(3*x+15))/3 = 0
(3*(2*x+10))/(2*3)+(-1*2*(3*x+15))/(2*3) = 0
3*(2*x+10)-1*2*(3*x+15) = 0
0 = 0
0/(2*3) = 0
0/(2*3) = 0 // * 2*3
0 = 0
x belongs to the empty set
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