(2x+10)(x+6)=2x2+22x+60

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Solution for (2x+10)(x+6)=2x2+22x+60 equation: 



(2x+10)(x+6)=2x^2+22x+60

We move all terms to the left:

(2x+10)(x+6)-(2x^2+22x+60)=0

We get rid of parentheses

-2x^2+(2x+10)(x+6)-22x-60=0

We multiply parentheses ..

-2x^2+(+2x^2+12x+10x+60)-22x-60=0

We get rid of parentheses

-2x^2+2x^2+12x+10x-22x+60-60=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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