(2x+10)(x+3)=0

Solution for (2x+10)(x+3)=0 equation:

(2x+10)(x+3)=0

We multiply parentheses ..

(+2x^2+6x+10x+30)=0

We get rid of parentheses

2x^2+6x+10x+30=0

We add all the numbers together, and all the variables

2x^2+16x+30=0

a = 2; b = 16; c = +30;
Δ = b2-4ac
Δ = 162-4·2·30
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*2}=\frac{-20}{4}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*2}=\frac{-12}{4}
=-3
$