(2x+1)=3(x-5)

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Solution for (2x+1)=3(x-5) equation: 



(2x+1)=3(x-5)

We move all terms to the left:

(2x+1)-(3(x-5))=0

We get rid of parentheses

2x-(3(x-5))+1=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

2x-3x+15+1=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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