(2x+1)=3(3x-4)+5

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Solution for (2x+1)=3(3x-4)+5 equation: 



(2x+1)=3(3x-4)+5

We move all terms to the left:

(2x+1)-(3(3x-4)+5)=0

We get rid of parentheses

2x-(3(3x-4)+5)+1=0



We calculate terms in parentheses: -(3(3x-4)+5), so:

3(3x-4)+5

We multiply parentheses

9x-12+5

We add all the numbers together, and all the variables

9x-7

Back to the equation:

-(9x-7)



We get rid of parentheses

2x-9x+7+1=0

We add all the numbers together, and all the variables

-7x+8=0

We move all terms containing x to the left, all other terms to the right

-7x=-8

x=-8/-7

x=1+1/7

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