(2x+1)=27+3(2x-5)

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Solution for (2x+1)=27+3(2x-5) equation: 



(2x+1)=27+3(2x-5)

We move all terms to the left:

(2x+1)-(27+3(2x-5))=0

We get rid of parentheses

2x-(27+3(2x-5))+1=0



We calculate terms in parentheses: -(27+3(2x-5)), so:

27+3(2x-5)

determiningTheFunctionDomain
3(2x-5)+27

We multiply parentheses

6x-15+27

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

2x-6x-12+1=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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