(2x+1)/5=(x-2)/2

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Solution for (2x+1)/5=(x-2)/2 equation: 



(2x+1)/5=(x-2)/2

We move all terms to the left:

(2x+1)/5-((x-2)/2)=0

We calculate fractions


2x/()+(-((x-2)*5)/()=0



We calculate terms in parentheses: +(-((x-2)*5)/(), so:

-((x-2)*5)/(

We multiply all the terms by the denominator


-((x-2)*5)



We calculate terms in parentheses: -((x-2)*5), so:

(x-2)*5

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

-5x+10

Back to the equation:

+(-5x+10)



We get rid of parentheses

2x/()-5x+10=0

We multiply all the terms by the denominator


2x-5x*()+10*()=0

We add all the numbers together, and all the variables

2x-5x*()=0

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