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(2x+1)/3=4x+5
We move all terms to the left:
(2x+1)/3-(4x+5)=0
We get rid of parentheses
(2x+1)/3-4x-5=0
We multiply all the terms by the denominator
(2x+1)-4x*3-5*3=0
We add all the numbers together, and all the variables
(2x+1)-4x*3-15=0
Wy multiply elements
(2x+1)-12x-15=0
We get rid of parentheses
2x-12x+1-15=0
We add all the numbers together, and all the variables
-10x-14=0
We move all terms containing x to the left, all other terms to the right
-10x=14
x=14/-10
x=-1+2/5
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