(2x+1)/3=(x+5)/2

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Solution for (2x+1)/3=(x+5)/2 equation: 



(2x+1)/3=(x+5)/2

We move all terms to the left:

(2x+1)/3-((x+5)/2)=0

We calculate fractions


2x/()+(-((x+5)*3)/()=0



We calculate terms in parentheses: +(-((x+5)*3)/(), so:

-((x+5)*3)/(

We multiply all the terms by the denominator


-((x+5)*3)



We calculate terms in parentheses: -((x+5)*3), so:

(x+5)*3

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-3x-15

Back to the equation:

+(-3x-15)



We get rid of parentheses

2x/()-3x-15=0

We multiply all the terms by the denominator


2x-3x*()-15*()=0

We add all the numbers together, and all the variables

2x-3x*()=0

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