(2x+1)/3=(x+2)/2

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Solution for (2x+1)/3=(x+2)/2 equation: 



(2x+1)/3=(x+2)/2

We move all terms to the left:

(2x+1)/3-((x+2)/2)=0

We calculate fractions


2x/()+(-((x+2)*3)/()=0



We calculate terms in parentheses: +(-((x+2)*3)/(), so:

-((x+2)*3)/(

We multiply all the terms by the denominator


-((x+2)*3)



We calculate terms in parentheses: -((x+2)*3), so:

(x+2)*3

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

-3x-6

Back to the equation:

+(-3x-6)



We get rid of parentheses

2x/()-3x-6=0

We multiply all the terms by the denominator


2x-3x*()-6*()=0

We add all the numbers together, and all the variables

2x-3x*()=0

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