(2x+1)/2=(x+8)/5

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Solution for (2x+1)/2=(x+8)/5 equation: 



(2x+1)/2=(x+8)/5

We move all terms to the left:

(2x+1)/2-((x+8)/5)=0

We calculate fractions


2x/()+(-((x+8)*2)/()=0



We calculate terms in parentheses: +(-((x+8)*2)/(), so:

-((x+8)*2)/(

We multiply all the terms by the denominator


-((x+8)*2)



We calculate terms in parentheses: -((x+8)*2), so:

(x+8)*2

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

-2x-16

Back to the equation:

+(-2x-16)



We get rid of parentheses

2x/()-2x-16=0

We multiply all the terms by the denominator


2x-2x*()-16*()=0

We add all the numbers together, and all the variables

2x-2x*()=0

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