(2x+1)/(x+3)=1+(x+3)/(x-1)

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Solution for (2x+1)/(x+3)=1+(x+3)/(x-1) equation: 


D( x )

x+3 = 0

x-1 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-3) U (-3:1) U (1:+oo)

(2*x+1)/(x+3) = (x+3)/(x-1)+1 // - (x+3)/(x-1)+1

(2*x+1)/(x+3)-((x+3)/(x-1))-1 = 0

(2*x+1)/(x+3)+(-1*(x+3))/(x-1)-1 = 0

((2*x+1)*(x-1))/((x+3)*(x-1))+(-1*(x+3)^2)/((x+3)*(x-1))+(-1*(x+3)*(x-1))/((x+3)*(x-1)) = 0

(2*x+1)*(x-1)-1*(x+3)^2-1*(x+3)*(x-1) = 0

x^2-x^2-7*x-2*x-10+3 = 0

-9*x-7 = 0

(-9*x-7)/((x+3)*(x-1)) = 0

(-9*x-7)/((x+3)*(x-1)) = 0 // * (x+3)*(x-1)

-9*x-7 = 0

-9*x-7 = 0 // + 7

-9*x = 7 // : -9

x = 7/(-9)

x = -7/9

x = -7/9

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