(2x+1)/(3x-2)=2

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Solution for (2x+1)/(3x-2)=2 equation:



(2x+1)/(3x-2)=2
We move all terms to the left:
(2x+1)/(3x-2)-(2)=0
Domain of the equation: (3x-2)!=0
We move all terms containing x to the left, all other terms to the right
3x!=2
x!=2/3
x!=2/3
x∈R
We multiply all the terms by the denominator
(2x+1)-2*(3x-2)=0
We multiply parentheses
(2x+1)-6x+4=0
We get rid of parentheses
2x-6x+1+4=0
We add all the numbers together, and all the variables
-4x+5=0
We move all terms containing x to the left, all other terms to the right
-4x=-5
x=-5/-4
x=1+1/4

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