(2x+1)+(x-3)+(4x)+(5)=

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Solution for (2x+1)+(x-3)+(4x)+(5)= equation:


Simplifying
(2x + 1) + (x + -3) + (4x) + (5) = 0

Reorder the terms:
(1 + 2x) + (x + -3) + (4x) + (5) = 0

Remove parenthesis around (1 + 2x)
1 + 2x + (x + -3) + (4x) + (5) = 0

Reorder the terms:
1 + 2x + (-3 + x) + (4x) + (5) = 0

Remove parenthesis around (-3 + x)
1 + 2x + -3 + x + (4x) + (5) = 0
1 + 2x + -3 + x + (4x) + 5 = 0

Reorder the terms:
1 + -3 + 5 + 2x + x + (4x) = 0

Combine like terms: 1 + -3 = -2
-2 + 5 + 2x + x + (4x) = 0

Combine like terms: -2 + 5 = 3
3 + 2x + x + (4x) = 0

Combine like terms: 2x + x = 3x
3 + 3x + (4x) = 0

Combine like terms: 3x + (4x) = 7x
3 + 7x = 0

Solving
3 + 7x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 7x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 7x = 0 + -3
7x = 0 + -3

Combine like terms: 0 + -3 = -3
7x = -3

Divide each side by '7'.
x = -0.4285714286

Simplifying
x = -0.4285714286

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