(2x+1)+(12-4x)+(8x-5)+(6+2x)=0

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Solution for (2x+1)+(12-4x)+(8x-5)+(6+2x)=0 equation: 



(2x+1)+(12-4x)+(8x-5)+(6+2x)=0

We add all the numbers together, and all the variables

(2x+1)+(-4x+12)+(8x-5)+(2x+6)=0

We get rid of parentheses

2x-4x+8x+2x+1+12-5+6=0

We add all the numbers together, and all the variables

8x+14=0

We move all terms containing x to the left, all other terms to the right

8x=-14

x=-14/8

x=-1+3/4

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