(2x+1)*(2x-1)=

Solution for (2x+1)*(2x-1)= equation:

Simplifying
(2x + 1)(2x + -1) = 0

Reorder the terms:
(1 + 2x)(2x + -1) = 0

Reorder the terms:
(1 + 2x)(-1 + 2x) = 0

Multiply (1 + 2x) * (-1 + 2x)
(1(-1 + 2x) + 2x * (-1 + 2x)) = 0
((-1 * 1 + 2x * 1) + 2x * (-1 + 2x)) = 0
((-1 + 2x) + 2x * (-1 + 2x)) = 0
(-1 + 2x + (-1 * 2x + 2x * 2x)) = 0
(-1 + 2x + (-2x + 4x2)) = 0

Combine like terms: 2x + -2x = 0
(-1 + 0 + 4x2) = 0
(-1 + 4x2) = 0

Solving
-1 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 4x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 4x2 = 0 + 1
4x2 = 0 + 1

Combine like terms: 0 + 1 = 1
4x2 = 1

Divide each side by '4'.
x2 = 0.25

Simplifying
x2 = 0.25

Take the square root of each side:
x = {-0.5, 0.5}