(2x+1)(x-4)-2x2=-4(1-3x)

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Solution for (2x+1)(x-4)-2x2=-4(1-3x) equation: 



(2x+1)(x-4)-2x^2=-4(1-3x)

We move all terms to the left:

(2x+1)(x-4)-2x^2-(-4(1-3x))=0

We add all the numbers together, and all the variables

-2x^2+(2x+1)(x-4)-(-4(-3x+1))=0

We multiply parentheses ..

-2x^2+(+2x^2-8x+x-4)-(-4(-3x+1))=0



We calculate terms in parentheses: -(-4(-3x+1)), so:

-4(-3x+1)

We multiply parentheses

12x-4

Back to the equation:

-(12x-4)



We get rid of parentheses

-2x^2+2x^2-8x+x-12x-4+4=0

We add all the numbers together, and all the variables

-19x=0

x=0/-19

x=0

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