(2x+1)(x-1)+x2=3(x-1)(x+2)-3

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Solution for (2x+1)(x-1)+x2=3(x-1)(x+2)-3 equation: 



(2x+1)(x-1)+x2=3(x-1)(x+2)-3

We move all terms to the left:

(2x+1)(x-1)+x2-(3(x-1)(x+2)-3)=0

We add all the numbers together, and all the variables

x^2+(2x+1)(x-1)-(3(x-1)(x+2)-3)=0

We multiply parentheses ..

x^2+(+2x^2-2x+x-1)-(3(x-1)(x+2)-3)=0



We calculate terms in parentheses: -(3(x-1)(x+2)-3), so:

3(x-1)(x+2)-3

We multiply parentheses ..

3(+x^2+2x-1x-2)-3

We multiply parentheses

3x^2+6x-3x-6-3

We add all the numbers together, and all the variables

3x^2+3x-9

Back to the equation:

-(3x^2+3x-9)



We get rid of parentheses

x^2+2x^2-3x^2-2x+x-3x-1+9=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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