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(2x+1)(x+10)=90
We move all terms to the left:
(2x+1)(x+10)-(90)=0
We multiply parentheses ..
(+2x^2+20x+x+10)-90=0
We get rid of parentheses
2x^2+20x+x+10-90=0
We add all the numbers together, and all the variables
2x^2+21x-80=0
a = 2; b = 21; c = -80;
Δ = b2-4ac
Δ = 212-4·2·(-80)
Δ = 1081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{1081}}{2*2}=\frac{-21-\sqrt{1081}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{1081}}{2*2}=\frac{-21+\sqrt{1081}}{4} $
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