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(2x+1)(x+1)=1-2x
We move all terms to the left:
(2x+1)(x+1)-(1-2x)=0
We add all the numbers together, and all the variables
(2x+1)(x+1)-(-2x+1)=0
We get rid of parentheses
(2x+1)(x+1)+2x-1=0
We multiply parentheses ..
(+2x^2+2x+x+1)+2x-1=0
We get rid of parentheses
2x^2+2x+x+2x+1-1=0
We add all the numbers together, and all the variables
2x^2+5x=0
a = 2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*2}=\frac{-10}{4} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*2}=\frac{0}{4} =0 $
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