(2x+1)(x+1)(x+2)=0

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Solution for (2x+1)(x+1)(x+2)=0 equation:


Simplifying
(2x + 1)(x + 1)(x + 2) = 0

Reorder the terms:
(1 + 2x)(x + 1)(x + 2) = 0

Reorder the terms:
(1 + 2x)(1 + x)(x + 2) = 0

Reorder the terms:
(1 + 2x)(1 + x)(2 + x) = 0

Multiply (1 + 2x) * (1 + x)
(1(1 + x) + 2x * (1 + x))(2 + x) = 0
((1 * 1 + x * 1) + 2x * (1 + x))(2 + x) = 0
((1 + 1x) + 2x * (1 + x))(2 + x) = 0
(1 + 1x + (1 * 2x + x * 2x))(2 + x) = 0
(1 + 1x + (2x + 2x2))(2 + x) = 0

Combine like terms: 1x + 2x = 3x
(1 + 3x + 2x2)(2 + x) = 0

Multiply (1 + 3x + 2x2) * (2 + x)
(1(2 + x) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
((2 * 1 + x * 1) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
((2 + 1x) + 3x * (2 + x) + 2x2 * (2 + x)) = 0
(2 + 1x + (2 * 3x + x * 3x) + 2x2 * (2 + x)) = 0
(2 + 1x + (6x + 3x2) + 2x2 * (2 + x)) = 0
(2 + 1x + 6x + 3x2 + (2 * 2x2 + x * 2x2)) = 0
(2 + 1x + 6x + 3x2 + (4x2 + 2x3)) = 0

Combine like terms: 1x + 6x = 7x
(2 + 7x + 3x2 + 4x2 + 2x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(2 + 7x + 7x2 + 2x3) = 0

Solving
2 + 7x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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