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(2x+1)(7+x-4x+2)=0
We add all the numbers together, and all the variables
(2x+1)(-3x+9)=0
We multiply parentheses ..
(-6x^2+18x-3x+9)=0
We get rid of parentheses
-6x^2+18x-3x+9=0
We add all the numbers together, and all the variables
-6x^2+15x+9=0
a = -6; b = 15; c = +9;
Δ = b2-4ac
Δ = 152-4·(-6)·9
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-21}{2*-6}=\frac{-36}{-12} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+21}{2*-6}=\frac{6}{-12} =-1/2 $
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