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(2x+1)(5x+5)=90
We move all terms to the left:
(2x+1)(5x+5)-(90)=0
We multiply parentheses ..
(+10x^2+10x+5x+5)-90=0
We get rid of parentheses
10x^2+10x+5x+5-90=0
We add all the numbers together, and all the variables
10x^2+15x-85=0
a = 10; b = 15; c = -85;
Δ = b2-4ac
Δ = 152-4·10·(-85)
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{145}}{2*10}=\frac{-15-5\sqrt{145}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{145}}{2*10}=\frac{-15+5\sqrt{145}}{20} $
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