(2x+1)(4x-5/7)=0

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Solution for (2x+1)(4x-5/7)=0 equation: 


x in (-oo:+oo)

(2*x+1)*(4*x-(5/7)) = 0

(2*x+1)*(4*x-5/7) = 0

( 2*x+1 )

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

( 4*x-5/7 )

4*x-5/7 = 0 // + 5/7

4*x = 5/7 // : 4

x = 5/7/4

x = 5/28

x in { -1/2, 5/28 }

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