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(2x+1)(4x+9)=0
We multiply parentheses ..
(+8x^2+18x+4x+9)=0
We get rid of parentheses
8x^2+18x+4x+9=0
We add all the numbers together, and all the variables
8x^2+22x+9=0
a = 8; b = 22; c = +9;
Δ = b2-4ac
Δ = 222-4·8·9
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-14}{2*8}=\frac{-36}{16} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+14}{2*8}=\frac{-8}{16} =-1/2 $
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