(2x+1)(2x-3)+x=(x+5)-22

Solution for (2x+1)(2x-3)+x=(x+5)-22 equation:

(2x+1)(2x-3)+x=(x+5)-22

We move all terms to the left:

(2x+1)(2x-3)+x-((x+5)-22)=0

We add all the numbers together, and all the variables

x+(2x+1)(2x-3)-((x+5)-22)=0

We multiply parentheses ..

(+4x^2-6x+2x-3)+x-((x+5)-22)=0


We calculate terms in parentheses: -((x+5)-22), so:

(x+5)-22

We get rid of parentheses

x+5-22

We add all the numbers together, and all the variables

x-17

Back to the equation:

-(x-17)


We get rid of parentheses

4x^2-6x+2x+x-x-3+17=0

We add all the numbers together, and all the variables

4x^2-4x+14=0

a = 4; b = -4; c = +14;
Δ = b2-4ac
Δ = -42-4·4·14
Δ = -208
Delta is less than zero, so there is no solution for the equation