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(2x+1)(2x+3)=323
We move all terms to the left:
(2x+1)(2x+3)-(323)=0
We multiply parentheses ..
(+4x^2+6x+2x+3)-323=0
We get rid of parentheses
4x^2+6x+2x+3-323=0
We add all the numbers together, and all the variables
4x^2+8x-320=0
a = 4; b = 8; c = -320;
Δ = b2-4ac
Δ = 82-4·4·(-320)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-72}{2*4}=\frac{-80}{8} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+72}{2*4}=\frac{64}{8} =8 $
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