(2x+1)(2x+1)-8(2x+1)=-15

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Solution for (2x+1)(2x+1)-8(2x+1)=-15 equation:


Simplifying
(2x + 1)(2x + 1) + -8(2x + 1) = -15

Reorder the terms:
(1 + 2x)(2x + 1) + -8(2x + 1) = -15

Reorder the terms:
(1 + 2x)(1 + 2x) + -8(2x + 1) = -15

Multiply (1 + 2x) * (1 + 2x)
(1(1 + 2x) + 2x * (1 + 2x)) + -8(2x + 1) = -15
((1 * 1 + 2x * 1) + 2x * (1 + 2x)) + -8(2x + 1) = -15
((1 + 2x) + 2x * (1 + 2x)) + -8(2x + 1) = -15
(1 + 2x + (1 * 2x + 2x * 2x)) + -8(2x + 1) = -15
(1 + 2x + (2x + 4x2)) + -8(2x + 1) = -15

Combine like terms: 2x + 2x = 4x
(1 + 4x + 4x2) + -8(2x + 1) = -15

Reorder the terms:
1 + 4x + 4x2 + -8(1 + 2x) = -15
1 + 4x + 4x2 + (1 * -8 + 2x * -8) = -15
1 + 4x + 4x2 + (-8 + -16x) = -15

Reorder the terms:
1 + -8 + 4x + -16x + 4x2 = -15

Combine like terms: 1 + -8 = -7
-7 + 4x + -16x + 4x2 = -15

Combine like terms: 4x + -16x = -12x
-7 + -12x + 4x2 = -15

Solving
-7 + -12x + 4x2 = -15

Solving for variable 'x'.

Reorder the terms:
-7 + 15 + -12x + 4x2 = -15 + 15

Combine like terms: -7 + 15 = 8
8 + -12x + 4x2 = -15 + 15

Combine like terms: -15 + 15 = 0
8 + -12x + 4x2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(2 + -3x + x2) = 0

Factor a trinomial.
4((1 + -1x)(2 + -1x)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {1, 2}

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