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(2x+0.3)(2x+0.4)=2.624
We move all terms to the left:
(2x+0.3)(2x+0.4)-(2.624)=0
We add all the numbers together, and all the variables
(2x+0.3)(2x+0.4)-2.624=0
We multiply parentheses ..
(+4x^2+0.8x+0.6x+0.12)-2.624=0
We get rid of parentheses
4x^2+0.8x+0.6x+0.12-2.624=0
We add all the numbers together, and all the variables
4x^2+1.4x-2.504=0
a = 4; b = 1.4; c = -2.504;
Δ = b2-4ac
Δ = 1.42-4·4·(-2.504)
Δ = 42.024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{42.024}}{2*4}=\frac{-1.4-\sqrt{42.024}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{42.024}}{2*4}=\frac{-1.4+\sqrt{42.024}}{8} $
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