(2x+-11)(3x+7)=0

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Solution for (2x+-11)(3x+7)=0 equation:



(2x+-11)(3x+7)=0
We add all the numbers together, and all the variables
(2x-11)(3x+7)=0
We multiply parentheses ..
(+6x^2+14x-33x-77)=0
We get rid of parentheses
6x^2+14x-33x-77=0
We add all the numbers together, and all the variables
6x^2-19x-77=0
a = 6; b = -19; c = -77;
Δ = b2-4ac
Δ = -192-4·6·(-77)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-47}{2*6}=\frac{-28}{12} =-2+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+47}{2*6}=\frac{66}{12} =5+1/2 $

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