(2x)2-35x+98=0

Solution for (2x)2-35x+98=0 equation:

(2x)2-35x+98=0

We add all the numbers together, and all the variables

2x^2-35x+98=0

a = 2; b = -35; c = +98;
Δ = b2-4ac
Δ = -352-4·2·98
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-21}{2*2}=\frac{14}{4}
=3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+21}{2*2}=\frac{56}{4}
=14
$