(2x)/(x+1)-5/(2x)=2

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Solution for (2x)/(x+1)-5/(2x)=2 equation: 



(2x)/(x+1)-5/(2x)=2

We move all terms to the left:

(2x)/(x+1)-5/(2x)-(2)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We calculate fractions


4x^2/(2x^2+2x)+(-5x-5)/(2x^2+2x)-2=0

We multiply all the terms by the denominator


4x^2+(-5x-5)-2*(2x^2+2x)=0

We multiply parentheses

4x^2-4x^2+(-5x-5)-4x=0

We get rid of parentheses

4x^2-4x^2-5x-4x-5=0

We add all the numbers together, and all the variables

-9x-5=0

We move all terms containing x to the left, all other terms to the right

-9x=5

x=5/-9

x=-5/9

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