(2x)/(5+7)=(3x+2)/6

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Solution for (2x)/(5+7)=(3x+2)/6 equation: 



(2x)/(5+7)=(3x+2)/6

We move all terms to the left:

(2x)/(5+7)-((3x+2)/6)=0

We add all the numbers together, and all the variables

2x/12-((3x+2)/6)=0

We calculate fractions


12x^2/()+(-((3x+2)*12)/()=0



We calculate terms in parentheses: +(-((3x+2)*12)/(), so:

-((3x+2)*12)/(

We multiply all the terms by the denominator


-((3x+2)*12)



We calculate terms in parentheses: -((3x+2)*12), so:

(3x+2)*12

We multiply parentheses

36x+24

Back to the equation:

-(36x+24)



We get rid of parentheses

-36x-24

Back to the equation:

+(-36x-24)



We get rid of parentheses

12x^2/()-36x-24=0

We multiply all the terms by the denominator


12x^2-36x*()-24*()=0

We add all the numbers together, and all the variables

12x^2-36x*()=0

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