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(2x)+(x-5)+(3x/5)=180
We move all terms to the left:
(2x)+(x-5)+(3x/5)-(180)=0
We add all the numbers together, and all the variables
2x+(x-5)+(+3x/5)-180=0
We get rid of parentheses
2x+x+3x/5-5-180=0
We multiply all the terms by the denominator
2x*5+x*5+3x-5*5-180*5=0
We add all the numbers together, and all the variables
3x+2x*5+x*5-925=0
Wy multiply elements
3x+10x+5x-925=0
We add all the numbers together, and all the variables
18x-925=0
We move all terms containing x to the left, all other terms to the right
18x=925
x=925/18
x=51+7/18
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