(2x)+(x+2)=58

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Solution for (2x)+(x+2)=58 equation: 



(2x)+(x+2)=58

We move all terms to the left:

(2x)+(x+2)-(58)=0

We get rid of parentheses

2x+x+2-58=0

We add all the numbers together, and all the variables

3x-56=0

We move all terms containing x to the left, all other terms to the right

3x=56

x=56/3

x=18+2/3

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