(2x)+(7x-12)+(4x)+(4x+2)+(5x)=540

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Solution for (2x)+(7x-12)+(4x)+(4x+2)+(5x)=540 equation: 



(2x)+(7x-12)+(4x)+(4x+2)+(5x)=540

We move all terms to the left:

(2x)+(7x-12)+(4x)+(4x+2)+(5x)-(540)=0

We add all the numbers together, and all the variables

11x+(7x-12)+(4x+2)-540=0

We get rid of parentheses

11x+7x+4x-12+2-540=0

We add all the numbers together, and all the variables

22x-550=0

We move all terms containing x to the left, all other terms to the right

22x=550

x=550/22

x=25

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