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(2x)+(3x-1)=137-x
We move all terms to the left:
(2x)+(3x-1)-(137-x)=0
We add all the numbers together, and all the variables
2x+(3x-1)-(-1x+137)=0
We get rid of parentheses
2x+3x+1x-1-137=0
We add all the numbers together, and all the variables
6x-138=0
We move all terms containing x to the left, all other terms to the right
6x=138
x=138/6
x=23
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