(2x)+(128x2)=360

Solution for (2x)+(128x2)=360 equation:

(2x)+(128x^2)=360

We move all terms to the left:

(2x)+(128x^2)-(360)=0

determiningTheFunctionDomain
128x^2+2x-360=0

a = 128; b = 2; c = -360;
Δ = b2-4ac
Δ = 22-4·128·(-360)
Δ = 184324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{184324}=\sqrt{4*46081}=\sqrt{4}*\sqrt{46081}=2\sqrt{46081}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{46081}}{2*128}=\frac{-2-2\sqrt{46081}}{256}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{46081}}{2*128}=\frac{-2+2\sqrt{46081}}{256}
$